These expressions are given as exponential functions
O = Eoe(io)
R = Ere(ir)
where
O - Object wave
R - Reference wave
I - Intensity
E - Amplitude
- Phase angle
We can write the formula for the intensity in the hologram
I = (O + R) (O* + R*) (3.1a)
= (Eoeio + Erei
r
) . (Eoe-i
o + Ere-i
r
) (3.1b)
= Eo2eio-i
o + EoErei(
o-
r)
+ ErEoe-(
o-
r) + Er2ei
r-i
r
(3.1c)
= Eo2 + Er2
+ EoErei(o-
r) + EoEre-i(
o-
r)
(3.1d)
The phase information is contained in the two last terms.
While an ordinary picture records only the intensity distribution
in the object, the hologram contains also information about the
phase. It means all information about the object is saved in the
hologram, and we get an image in 3 dimensions.
A transmission distribution can be carried out for when the film
plate is exposed
Where
T = Transmission distribution on the filmplate
T0 Transmission constant for the filmplate
= Film parameter
I = Exposure intensity
t = Exposure time
We have the following function for the transmission distribution
T = T0 -
It (3.2)
We put in the formula for the intensity (3.1d) into formula (3.2),
and we get for the transmission distribution
T = T0 -
(Eo2 + Er2
+ EoErei(o-r) + EoEre-i(
o-
r)
)t (3.3a)
T = T0 -
t (Eo2 +
Er2 )-
t EoEr(ei(o-r) + e-i(o-
r)
) (3.3b)
This equation describes the exposure of a holographic filmplate. This means that the equation describes a hologram.
For the reconstruction of the hologram, we have to illuminate
the holographic plate with a beam which is similar or nearly similar
to the reference beam.
The reconstruction can then be expressed as
ER = Er eiR
T (3.4)
The use of R instead of r is justified as the reconstruction
beam is not necessarily the same as the reference beam.
ER = Er eiR
T0 - Er ei
R
t (Eo2
+ Er2) - Er eiR
tEoEr
(ei(o-
r) + e-i(
o-
r) ) (3.5a)
This equation can also be written as
ER =
-tErEo2ei
R + Erei
R
(T0-
tEr2) (3.5b)
-
tEoEr2ei(o-
r+
R)
- tEoEr2ei(-
o+
r+
R)
The first term of the equation (3.5b) represents a wave which
travels in EreiR
direction.25
Er is a wave which spreads from the object and is not
constant. The wave is a function of (x,y).
The second term represents the virtual image. If the phase of
the reference and reconstruction wave is equal, the second term
will be identical to the object wave, with the exception of the
amplitude. We have also reconstructed the object completely.
The third term represent the real image. Except for small angles
( r) will it not be possible to see the virtual and
the real image at the same time. From the equation (3.5b) we can
see that the phase of the object wave (
o ) is positive
for the real image and negative for the virtual image. This means
that the virtual image and the real image lie on opposite sides
of the holographic filmplate.
The real image is created by waves which travel in the positive direction. This direction is the same as the direction of the reference beam.
The virtual image is created by waves which travel in the negative
direction, which is in the opposite direction to the reference
beam.
Figure 3-1 Reconstruction of a hologram